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The molarity (m) of an aqueous solution containing 22.5 g of glucose (c6h12o6) in 35.5 ml of solution is ________.

User Shriyog
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2 Answers

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Molarity is found by dividing moles of solute/liters of solution. First, find the molar mass of glucose:

22.5 grams C6H12O6 x(1 mole/180 grams) = 0.125 moles glucose

Then, divide moles over liters:
M=0.125 moles glucose/0.035 L sol'n
M=3.57

User Autocrab
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Step-by-step explanation:

Molarity is the number of moles present in a liter of solution.

Mathematically, Molarity =
\frac{\text{no. of moles}}{\text{volume in liter}}

And, no. of moles =
\frac{mass}{\text{molar mass}}

Molar mass of
C_(6)H_(12)O_(6) is 180.15 g/mol. Therefore, number of moles present will be as follows.

No. of moles =
\frac{mass}{\text{molar mass}}

=
(22.5 g)/(180.15 g/mol)

= 0.124 mol

Hence, calculate the molarity as follows.

Molarity =
\frac{\text{no. of moles}}{\text{volume in liter}}

=
(0.124 mol)/(0.0355 L) (as 1 L = 1000 mL)

= 3.51 M

Thus, we can conclude that molarity of the solution is 3.51 M.

User Jdnoon
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