Question

The molarity (m) of an aqueous solution containing 22.5 g of glucose (c6h12o6) in 35.5 ml of solution is ________.

Answer 1

Molarity is found by dividing moles of solute/liters of solution. First, find the molar mass of glucose:

22.5 grams C6H12O6 x(1 mole/180 grams) = 0.125 moles glucose

Then, divide moles over liters:
M=0.125 moles glucose/0.035 L sol'n
M=3.57

Answer 2

Step-by-step explanation:

Molarity is the number of moles present in a liter of solution.

Mathematically, Molarity =
`\frac{\text{no. of moles}}{\text{volume in liter}}`

And, no. of moles =
`\frac{mass}{\text{molar mass}}`

Molar mass of
`C_(6)H_(12)O_(6)` is 180.15 g/mol. Therefore, number of moles present will be as follows.

No. of moles =
`\frac{mass}{\text{molar mass}}`

=
`(22.5 g)/(180.15 g/mol)`

= 0.124 mol

Hence, calculate the molarity as follows.

Molarity =
`\frac{\text{no. of moles}}{\text{volume in liter}}`

=
`(0.124 mol)/(0.0355 L)` (as 1 L = 1000 mL)

= 3.51 M

Thus, we can conclude that molarity of the solution is 3.51 M.