Question

Which function has a vertex at the origin?

f(x) = (x + 4)^2
f(x) = x(x – 4)
f(x) = (x – 4)(x + 4)
f(x) = –x^2

Answer 1

fdx = x-4 2

Step-by-step explanation:The test was right

Answer 2

`\bf \qquad \textit{parabola vertex form}\\\\ \begin{array}{llll} y=a(x-{{ h}})^2+{{ k}}\\\\ x=a(y-{{ k}})^2+{{ h}} \end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -------------------------------\\\\ -x^2\implies -(x-\stackrel{h}{0})^2\stackrel{k}{+0}`