143k views
3 votes
How do you put (x+5)(x-3)[x-(4-i)][x-(4+i)] into standard form

1 Answer

6 votes

(x+5)(x-3)[x-(4-i)][x-(4+i)] \\ (x^(2)+5x-3x-15)(x-4+i)(x-4-i) \\ (x^(2)+5x-3x-15)(x^(2) -4x-xi-4x+16+4i+xi-4i- i^(2) ) \\ (x^(2)+5x-3x-15)( x^(2) -8x+16- i^(2)) \\ (x^(2)+5x-3x-15)( x^(2) -8x+16-(-1)) \\ (x^(2)+5x-3x-15)( x^(2) -8x+16+1) \\ (x^(2)+5x-3x-15)( x^(2) -8x+17)
From there just distribute and simplify.
User Adam Miklosi
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.