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Help!? i dont understand. First question on top, and second question in bottom

Help!? i dont understand. First question on top, and second question in bottom-example-1
User Inon Peled
by
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1 Answer

1 vote
We know that:


$\sqrt[a]{x^b}=x^{(b)/(a)}

so:

1)


$(\sqrt[3]{t^4})\cdot(t^{(-1)/(2)})=(t^{(4)/(3)})\cdot(t^{(-1)/(2)})= t^{(4)/(3)+(-1)/(2)}=t^{(8)/(6)+(-3)/(6)}=t^{(8-3)/(6)}=\boxed{t^{(5)/(6)}=\sqrt[6]{t^5}}

2)


x^{-(2)/(5)}=\frac{1}{x^{(2)/(5)}}=\boxed{\frac{1}{\sqrt[5]{x^2}}}

Answer 4)
User Suraj Bhatia
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