A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the ball?

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asked Dec 3, 2018 176k views

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Akinola Olayinka · Answer 1 · 2018-12-09T14:01:19+0000

Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.

By definition, the impulse is

$I = \int_(0)^(2) F(t) dt = \int _(0)^(2) 39dt = 39*2=78 \, N-s$

Answer: 78 N-s

A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the ball?

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