Question

A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the ball?

Answer 1

78 N - S

Step-by-step explanation:

It is correct

Answer 2

Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.

By definition, the impulse is

`I = \int_(0)^(2) F(t) dt = \int _(0)^(2) 39dt = 39*2=78 \, N-s`

Answer: 78 N-s