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A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t2+ 440t. After how many seconds does it reach its maximum height?
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A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t2+ 440t. After how many seconds does it reach its maximum height?
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Jan 23, 2018
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A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t2+ 440t. After how many seconds does it reach its maximum height?
Mathematics
high-school
DeJaVo
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Attached the solution and work.
Alvi
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Jan 29, 2018
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