Question

Larry mixed 15 grams of salt with 210 grams of a 5% salt solution in water. What is the percent of salt in his new solution?

Answer 1

11.33% hope it helps
have a great day :)

Answer 2

11.33%

Explanation:

Amount of salt which Larry has to mix= 15 grams

In 210 gm of salt solution, content of salt= 5%

Amount of salt in salt solution= 5 % of 210 grams

Amount of salt in salt solution=
`(5)/(100)` of 210 grams

Amount of salt in salt solution=
`(21)/(2)`

Amount of salt in salt solution= 10.5 grams

Now the 15 grams of salt have to mix with 5% of salt solution

Total amount of salt= 15+ 10.5

Total amount of salt = 25.5 gram

Total amount of salt solution=15+ 210= 225 grams

Percentage of salt in new solution=
`(amount of new salt)/( amount of new solution)` ×100

Percentage of salt in new solution=
`(25.5)/( 225)` ×100

Percentage of salt in new solution= 0.13333×100

Percentage of salt in new solution= 11.33% (approx)

Hence, the correct answer is 11.33%