Question

Mike hiked to a lake in 6.5 hours at an average rate of 3 2/5 miles per hour. Pedro hiked the same distance at a rate of 3 4/5 miles per hour. How long did it take Pedro to reach the lake? Round to the hundredths place.

Answer 1

We first need to find the distance.
The information about Mike will provide the distance we need to answer the question about Pedro.

We will use D = rt

Mike:

(6.5)((17/5) = D

22.1 miles = D

Pedro:

D = rt

22.1 = (19/5)t

We need to find t.

22.1 ÷ 3.8 = t

5.8157894737 = t

We now round off as instructed.

5.82 = t

It took Pedro 5.82 hours to reach the lake.

Answer 2

5.82 hours.

Explanation:

We know that,

Distance = Time × Speed,

If the average rate of Mike =
`3(2)/(5)` miles per hour,

Time taken by him = 6.5 hours,

So, the distance he covered =
`6.5* 3(2)/(5)`

`=6.5* (17)/(5)`

`=1.3* 17`

`=22.1\text{ miles}`

If the average rate is
`3(4)/(5)` miles per hour to complete this distance,

Then time taken =
`(Distance)/(Speed)`

`=(22.1)/(3(4)/(5))`

`=(22.1* 5)/(19)`

`=(110.5)/(19)`

≈ 5.82

Thus, the time taken by Pedro would be 5.82 hours.