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What is the smallest integer that can be added to -2m^3-m+m^2+1 to make it completely divisible by m+1?

What is the smallest integer that can be added to -2m^3-m+m^2+1 to make it completely divisible by m+1?
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What is the smallest integer that can be added to -2m^3-m+m^2+1 to make it completely divisible by m+1?

User Sebastian Roth
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1 Answer

2 votes
Hello,

-2m^3+m^2-m+1=(m+1)(-2m^2+3m-4)+5

The smallest integer to add is -5.
User Yogesh Badke
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8.4k points
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