Question

What are the necessary criteria for a line to be perpendicular to the given line and have the same y-intercept?

Answer 1

y=-(3/5)x-7is the anwser because this is the form y=mx+b where m=5/3 any line perpendicular to this given line will have the slope of -1/m so, in this case slope of perpendicular is: -1/(5/3) = -3/5 we know the y-intercept is -7, point (0, -7) so wave: y = -(3/5)x - 7

Answer 2

The slope is -3/2 and contains the point (0, −2). Which is b.

Explanation:

(-3,-4) (3, 0)

slope = (0 +4) / (3 + 3) = 4/6 = 2/3

perpendicular so slope = -3/2

line on graph

y = mx + b

0 = 2/3 (3) + b

0 = 2+ b

b = -2

y intercept (0,-2)