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John had a roll containing 24 2/3 feet of wrapping paper. He wants to divide it into 11 pieces. First, though, he must cut off 5/6 foot because it was torn. How long will each piece be?

User Hasan
by
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2 Answers

3 votes

We are given a total size of 24 2/3 feet of wrapping paper. Convert this into fraction of denominator 6:

total paper = 24 2/3 = 74/3 = 148/6 feet

Subtract 5/6 foot:

remaining paper = 148/6 – 5/6 = 143/6 feet

Divide by 11:

each piece = (143/6) ft / 11 = 143/66 ft = 2.17 ft

User Holdenmcgrohen
by
6.4k points
3 votes

Given

John had a roll containing of wrapping paper


=24\tfrac{2}{3}

First, he must cut off 5/6 foot because it was torn.

He wants to divide it into 11 pieces.

To proof

As given in question

John had a roll containing of wrapping paper


=24\tfrac{2}{3}


=(74)/(3) ( solving the mixed fraction form)

First, though, he must cut off 5/6 foot

than we get


= (74)/(3) - (5)/(6)

Taking the L.C.M of 3 and 6 is 6


=(148-5)/(6)


=(143)/(6)

=23.83 feet (approx)

He wants to divide it into 11 piece

length of the each piece


=(23.83)/(11)

length of the each pieces be 2.16 feet ( approx)

Hence proved




User TheRiley
by
8.5k points
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