Question

The specific heat of ice is 0.5 calories/gram°C. 20 grams of ice will require _____ calories to raise the temperature 1°C. 0.5 1.0 5.0 10

Answer 1

0.5 x 20 = 10
The answer is 10.

Answer 2

10 calories

Step-by-step explanation:

The thermal energy needed to increase the temperature of a substance is given by

`Q=m C \Delta T`

where

m is the mass of the substance

C is the specific heat of the substance

`\Delta T` is the increase in temperature

In this problem, the mass of the ice is m=20 g, the specific heat is C=0.5 calories/gram°C, and the increase in temperature is
`\Delta T=1^(\circ)`. Therefore, the energy required is

`Q=(20 g)(0.5 cal/g^(\circ)C)(1^(\circ)C)=10 cal`