Question

By what percent will a fraction change if its numerator is increased by 60% and its denominator is decreased by 20%?

Answer 1

N/D --> 0.8N/0.4D = 2N/D

--> 100% increase
---------------
It's 100%, = 1 time larger, 2 times as large.

Answer 2

It is increased by 100%. The numerator is two times more than the denominator. That's why original fraction will become
`(2x)/(y)`.

Explanation:

We need to find the percentage, if its numerator is increases by 60% and its denominator decreases by 20%.

First, we let the original fraction:
`(x)/(y)`

We have given its numerator is increases by 60% and denominator is decreases by 20% then,

New fraction will become =
`(1.6x)/(0.8y)`.

Divide the new fraction by original fraction, then we get:

`(1.6x)/(0.8y)`/
`(x)/(y)`

`(1.6x)/(0.8y)`*
`(x)/(y)`

Then, it will become
`(1.6)/(0.8)`.

We can see that, The numerator is two times more than the denominator. That's why original fraction will become
`(2x)/(y)`.

It is increased by 100%.

If we take an example, Suppose the original fraction is
`(5)/(8)` and the new fraction will become
`(1.6*5)/(0.8*8)`.

=
`(8)/(6.4)` =
`(80)/(64)`

=
`(10)/(8)`, it is twice of original fraction
`(5)/(8)`.