Question

How do you do this problem

Answer 1

remember

`√(x^2)=x`
and

`\sqrt[3]{x^3}=x`

so

`√(x^2)+\sqrt[3]{y^3}=`

`x+y`



another way is this:
remember that

`\sqrt[n]{x^m}=x^(m)/(n)`
and remember that
`√(x)=\sqrt[2]{x}`

so

`√(x^2)+\sqrt[3]{y^3}=`

`x^(2)/(2)+y^(3)/(3)=`

`x^1+y^1=`

`x+y`

Answer 2

Square root x2 and then square root 3 and y3 with the exponents I belive you should try and use the Property of Power for this one.