Question

Find two consecutive even integers such that the smaller added to five times the larger gives a sum of 34

Answer 1

Let the first integer be represented by: 2k

and the second integer by: 2(k+1)

Then, 2k + 5[2(k+1)] = 34

2k + 10k + 10 = 34

12k + 10 = 34

12k = 24

k = 2

2k = 2(2) = 4

2(k + 1) = 2(2 + 1) = 6

Answer: 4 and 6