Question

How do you solve this quadratic equation, 3x2+4x-5=0

Answer 1

`3x^2+4x-5=0 \\ Solve\ using\ formular \ \ \ \boxed {x={ (-b\pm √(b^2-4ac) )/(2a) }} \\ \\ x={ (-4 \pm √(4^2-4(3)(-5)) )/(2(3)) }}`