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How do you solve this quadratic equation, 3x2+4x-5=0

User Xealot
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1 Answer

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3x^2+4x-5=0 \\ Solve\ using\ formular \ \ \ \boxed {x={ (-b\pm √(b^2-4ac) )/(2a) }} \\ \\ x={ (-4 \pm √(4^2-4(3)(-5)) )/(2(3)) }}
User Wbdarby
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