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Need help with this-example-1
User InTOWN
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P(1st number matching) = 1/49 (once drawn, 48 numbers remain)
P(2nd number matching) = 1/48 (once drawn, 47 numbers remain))
P(3rd number matching) = 1/47 (etc.)
P(4th number matching) = 1/46
P(5th number matching) = 1/45
P(6th number matching) = 1/44

At this points the odds of winning =
= 1/(49x48x47x46x45x44) = 1/(1.00683475x10¹⁰).

But since we can choose the 6 numbers in any order, then we have to divide (1.0068347x10¹⁰) by 6! (factorial 6 = 6x5x4x3x2x1= 720)

(1.00683475x10¹⁰)/6! = (1.00683475x10¹⁰)/720 = 13,983,816

And the P(of getting all 6 numbers) = 1/13,983,816


User Ben Sat
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