f(x) = x^3 - 2x^2 - 6x + 12 = 0
lets try substituting some of the factors of 12:-
f(2) = 8 - 8 -12+12 = 0 So one zero is x = 2 Answer
Dividing f(x) by (x - 2) we get:-
x^2 - 6 so the other 2 zeros are sqrt6 and - sqrt6 or 2.45 and -2.45 to the nearest hundredth Answer