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A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution? Use mc033-1.jpg. 0.327 M 4.29 M 6.00 M 7.35 M

User Rickster
by
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2 Answers

7 votes

Answer:

C. 6M

Step-by-step explanation:

EDGE 2021

User Frank Neblung
by
7.2k points
4 votes

Answer: The concentration of the stock solution will be 6.00 M.

Explanation: To calculate the molarity of the stock solution we use the formula:


M_1V_1=M_2V_2

where,


M_1\text{ and }V_1 are the molarity and volume of the stock solution.


M_2\text{ and }V_2 are the molarity and volume of the HCl solution.

Given:


M_1=?M\\V_1=35mL\\M_2=1.40M\\V_2=150mL

Putting values in above equation, we get:


M_1* 35=1.40* 150


M_1=6M

So, the concentration of the stock solution is 6M.

User Jaroslav Jandek
by
7.6k points
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