Answer:
Option A.
Explanation:
As it has been given in the figure attached,
Length of check-out area = Length of study area + length of Books
= 2 + 3
= 5 cm
Since Scale is 1 cm = 5 m
Then 5 cm Length = 5×5 m = 25 m
And width of check-out area = Total width - width of Books or study area
= 7 - 4
= 3 cm
Now with the help of scale, 3 cm width will be = 3×5 = 15 m
Therefore, actual dimensions of the check-out area will be 25×15 m
Option A is correct.