Question

Give the equation of a line that goes through the point (-14,-4) and is perpendicular to line -7x+5y=-15. Give your answer in slope intercept form

Answer 1

-7x + 5y = -15
5y = 7x - 15
y = 7/5x - 3....slope here is 7/5. A perpendicular line has a negative reciprocal slope. All that means s flip the original slope and change the sign. So the perpendicular line will need a slope of -5/7.

y = mx + b
slope(m) = -5/7
(-14,-4)...x = -14 and y = -4
now we sub and find b, the y int
-4 = -5/7(-14) + b
-4 = 10 + b
-4 - 10 = b
-14 = b

so ur perpendicular equation is : y = -5/7x - 14 <==