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Solve the inequality for b
10 ≥ - 2/3 (9+12B)

User Roetzi
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1 Answer

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10 \geq - (2)/(3) (9+12B)


10 \geq (-2)/(3)*9 +(-2)/(3)*12B


10 \geq (-2*3) +(-2*4B)


10 \geq -6 -8B


-8B \leq 10 + 6


-8B \leq 16


B \leq (16)/(-8) = -2

B ≤ -2

Hence, B is any number less than or equal to -2.
User Lundman
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