Question

Factor completely 16a^3b^7 + 2a^6 b4 − 22a ^4 b^5.

2(8a3b7 + a6b4 − 11a4b5)
2a3b4(8b3 + a3 − 11ab)
a3b4(16b3 + 2a3 − 22ab)
8b3 + a3 − 11ab

Answer 1

factor out 2a^3 from the epression
so it would become 2a^3b(8b^6 + a^3 * 4 - 11ab^4)
then you would use the communitive property to re order the terms
so your answer is 2a^3b * (8b^6 + 4a^3 - 11ab^4)

Answer 2

2a3b4(8b3 + a3 − 11ab)