the equation of a line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so
we see that the slope is rise/run=3/4
3 points we see are (-4,-6), (0,-3) and (4,0)
we get the equations
y+6=3/4(x+4)
y+3=3/4(x+0)
y+0=3/4(x+4)
answer is the first equaiton
y+6=3/4(x+4)