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The problem in the middle...how do you solve? The one that starts 27 1/3 [....

The problem in the middle...how do you solve? The one that starts 27 1/3 [....
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The problem in the middle...how do you solve? The one that starts 27 1/3 [....

The problem in the middle...how do you solve? The one that starts 27 1/3 [....-example-1
User Saeed Ahmadian
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1 Answer

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In PEMDAS, we do parenthesis first, so 2+4=6. Next, we have exponents. The cube root of 27 is 3, the square root of 4 is 2, and 6^2=36, getting
3*sqrt(36-6(4))=3*(sqrt(12))
User Lukad
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