Register
The problem in the middle...how do you solve? The one that starts 27 1/3 [....
23.6k views
0 votes
The problem in the middle...how do you solve? The one that starts 27 1/3 [....

The problem in the middle...how do you solve? The one that starts 27 1/3 [....-example-1
User Saeed Ahmadian
by
6.6k points

1 Answer

3 votes
In PEMDAS, we do parenthesis first, so 2+4=6. Next, we have exponents. The cube root of 27 is 3, the square root of 4 is 2, and 6^2=36, getting
3*sqrt(36-6(4))=3*(sqrt(12))
User Lukad
by
7.4k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.5m questions

10.0m answers

Other Questions

How do you estimate of 4 5/8 X 1/3
Write words to match the expression. 24- ( 6+3)
Please solve the following equation. x-6x=56
whats the most accurate estimation of 65+77
Find the additive inverse of 18/23
Link Copied!