Question

How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh? 5.55 g.

Answer 1

mCuSO4: 64+32+16+4 = 160 g/mol

6,02×10²³ ------- 160g
3,36×10²³ -------- X
X = (160×3,36×10²³)/6,02×10²³
X = 89,3 g

:•)

Answer 2

89.02g

Step-by-step explanation:

First you have to calculate how many grams weighs one mole of CuSO4.

Cu = 63.5g

S = 32g

O = 16 x 4 = 64g

1 mole CuSO4 = 159.5g

Then we have to know that 1 mole is
`6.022x10 ^(23)` molecules.

Now we calculate :

`159.5g=6.022x10^(23) molecules`

`x=3.36x10^(23) molecules`

`(3.36x10^(23) x 159.5)/(6.022x10^(23))=89.02g`