Question

Frank stands 400 feet from the base from the Statue of Liberty. If the Statue of Liberty is 306 feet tall, what is the angle of elevation from Frank to the top of the statue’s torch? Round the answer to the nearest tenth.

Answer 1

Top of Statue |
|
|
|
Frank -----------------------------------------------Base

Frank - Base = 400 ft
Base- Top statue = 360 feet
Angle of elevation =Angle Top-Franck-Base, let it be angle Ф

tan (Ф) = 360/400 = 0.9
arc tan (0.9) = tan⁻¹(0.9) = 41.98 ,

Ten angle of elevation Ф ≈ 42°

Answer 2

The answer is 36.9

Explanation:

We have a right angled triangle with an opposite of 300.5 ft. (306 - 5.5) and an adjacent of 400 ft. Recalling SOH CAH TOA, tanθ = O/A.

tan(θ) = 300.5/400.

θ = tan^-1(300.5/400).

θ = 36.9