* (in this question they didn't give me the volume of the cylinder or the height of the cylinder) -- the volume and height is NOT relevant.
the ball is 7.2 cm in diameter. Hence its volume is 4*(3.6)^3 * π/3
So, the volume the water occupies increases by this amount.
because the tank is cylindrical, this increase must also be cylindrical.
and the volume of the ïncreased cylinder is π*15^2 * h, where h is the increase in height of the water.
so h = (4*(3.6)^3 * π/3)/(π*15^2) = 4*(3.6)^3/(3*15^2)