Question

The length of a rectangle is 5 feet longer than its width. if the perimeter of the rectangle is 50 feet, find its area.

Answer 1

Let L be length and W be width.

L = 5 + W
So the perimeter is equal to 2L + 2W and that equals 50 feet.

So substitute L with 5 + W to get:

2(5+W) + 2W = 50
10 +2W + 2W = 50
10 + 4W = 50
4W = 40
W = 10
Which means:
L = 15

So the area is just LxW which is 15x10 = 150 feet squared