136k views
4 votes
How do you solve (x+3)-15=7(x-2)+8

User Danimt
by
8.2k points

2 Answers

7 votes
Solve using BEDMAS
(x+3)-15=7(x-2)+8
x+3-15=7(x-2)+8
x-12=7(x-2)+8
Distribute the Brackets
x-12=7(x-2)+8
x-12=7x-14+8
x-12=7x-6
Add 12 to both sides.
(x-12)+12=(7x-6)+12
x=7x+6
Subtract 7x from both sides
(x)-7x=(7x+6)-7x
-6x=6
Divide both sides by -6
(-6x)/-6=(6)/-6
x= -1

Hope this helps!
-Benjamin

User Azat Razetdinov
by
7.7k points
4 votes
(X+3)-15=7(x-2)+8
X+3-15=7x-14+8
X-12=7x-6
-7x -7x
-6x-12=-6
12 12
-6x/-6 6/-6

Answer: x= -1
User Akash Sharma
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories