Question

A rectangular athletic field is twice as long as it is wide. If the perimeter of the athletic field is 120 yards, what are the dimensions ? what is the width ?

Answer 1

L=2W
P=2(L+W)
P=120
120=2(L+W)
divide by 2
60=L+W
sub 2W for L
60=2W+W
60=3W
divide by 60 both sides
20=W

width=20 yd

Answer 2

Given:
`l=2w` and
`P=120yd` find
`l` and
`w`.


`P=2l+2w`

`120=2l+l`

`3l=120`

`l=40`


`l=2w`

`w=(l)/(2)`

`w=(40)/(2)`

`w=20`