Question

What is the amplitude of y = 1\2 sin 2x?

Answer 1

hello :
note : y = A sin(Bx + C) + d amplitude is A
in this exercise : A =1/2

Answer 2

The amplitude of given function is
`(1)/(2)`.

Explanation:

The given function is

`y=(1)/(2)\sin 2x` .... (1)

The standard form of sine function is

`y=A\sin(Bx+C)+D` ..... (2)

Where, A is amplitude,
`(2\pi)/(B)` is period, C is phase shift and D is mid line.

On comparing (1) and (2), we get

`A=(1)/(2)`

Therefore the amplitude of given function is
`(1)/(2)`.