Question

|Anyone able to help with math?

Which shows one way to determine the factors of x3 – 12x2 – 2x + 24 by grouping?

x(x2 – 12) + 2(x2 – 12)
x(x2 – 12) – 2(x2 – 12)
x2(x – 12) + 2(x – 12)
x2(x – 12) – 2(x – 12)

Answer 1

group into 2 groups, experiment

(x³-12x²)+(-2x+24)
factor
x²(x-12)-2(x-12)

so that is the 4th one