Question

What are the exact solutions of x^2 = 4 − 7x? x = x equals negative 7 plus or minus the square root of thirty-three all over 2 x = x equals negative 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of thirty-three all over 2

Answer 1

x equals negative 7 plus or minus the square root of 65 all over 2

Answer 2

(B) x equals negative 7 plus or minus the square root of sixty-five all over 2

Explanation:

The given equation is:

`x^2=4-7x`

Simplifying the above equation, we have

`x^2+7x-4=0`

Using the Quadratic formula, we get

`x=\frac{-7{\pm}√((7)^2-4(1)(-4))}{2}`

`x=\frac{-7{\pm}√(49+16)}{2}`

`x=\frac{-7{\pm}√(65)}{2}`

Hence, the exact solution of the given equation is x equals negative 7 plus or minus the square root of sixty-five all over 2.

Therefore, option (B) is correct.