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If the perimeter of a rectangular picture frame must be less than 180 in, and the width is 26 in, what must the height h of the frame be?

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You would form this inequality:

52 + 2x < (or equal to) 180

Then, solve as you would in an ordinary equation.

Subtract 52 from both sides of the sign. 180 - 52 = 128.

So, 2x is less than or equal to 128.
Divide 128 into two to get 64.

The height of the frame must be 64 inches.
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