Question

What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?

Answer 1

Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by

`pV=nRT \\ or \\ V= (nRT)/(p)`
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,

`V= ((12\,mol)(8.3145\, (J)/(mol-K) )(273\,K))/(75 * 10^(3) \, Pa)= 0.3632\,m^(3)`

Answer: 0.363 m³