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The outside of a picture frame measures 14 in and 20 in 196in^2 of the picture shows find the thickness of the frame

User Flopp
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The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width.
Area = Length x Height
Area = (20 in) x (14 in)
Area = 280 in²

We are given that the area is only equal to 192 in². We subtract this value from the computed area.
Difference = 280 in² - 192 in²
difference = 88 in²

This area is equal to the area of the hollow space inside the frame. That is equal to,
height = 20 in - 2x
length = 14 in - 2x

The area,
88 = (20 - 2x)(14 - 2x)

Simplify the right hand side of the equation.
88 = 280 - 68x + 4x²

Divide the equation by 4,
22 = 70 - 17x + x²

Transposing,
x² - 17x - 48 = 0
The factors of the equation is 58.2.

Thus, the thickenss is equal to 58.2 in
User Wirnse
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