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A bag contains 15 15 red candies, 15 15 yellow candies, and 15 15 blue candies. what is the probability of randomly choosing two candies of the same color, without replacement?

2 Answers

6 votes
Based on my calculations, this would be 10%.
User Dennis R
by
6.1k points
4 votes

Answer:


\texttt{Probability of choosing two candies of the same color}=(7)/(22)

Explanation:

Probability of choosing two candies of the same color = Probability of choosing 2 red candies + Probability of choosing 2 yellow candies + Probability of choosing 2 blue candies.

Number of total candies = 15+15+15 = 45

Number of red candies = 15


\texttt{Probability of choosing 2 red candies}=(15)/(45)* (14)/(44)=(1)/(3)* (7)/(22)=(7)/(66)

Number of yellow candies = 15


\texttt{Probability of choosing 2 yellow candies}=(15)/(45)* (14)/(44)=(1)/(3)* (7)/(22)=(7)/(66)

Number of blue candies = 15


\texttt{Probability of choosing 2 blue candies}=(15)/(45)* (14)/(44)=(1)/(3)* (7)/(22)=(7)/(66)


\texttt{Probability of choosing two candies of the same color}=(7)/(66)+(7)/(66)+(7)/(66)\\\\\texttt{Probability of choosing two candies of the same color}=(7)/(22)

User Henrov
by
5.7k points