How do i write the rational expression in simplest form

asked Jan 20, 2018 74.2k views

3 votes

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$\cfrac{4y-8y^2}{10y-5}= \cfrac{-(8y^2-4y)}{5(2y-1)}= \cfrac{-4y(2y-1)}{5(2y-1)}= -\cfrac{4y}{5}$

Winkbrace answered Jan 21, 2018

7.9k points

6 votes

4y(1 - 2y)
= --------------
5(2y - 1)

-4y(2y - 1)
= --------------
5(2y - 1)

= -4y / 5

hope it helps

Kyle Siegel answered Jan 25, 2018

8.8k points

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