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In a hospital ward, there are 12 nurses and 4 doctors. 3 of the nurses and 2 of the doctors are male. If a person is randomly selected from this group, what is the probability that the person is female or a doctor? @IMStuck @TheSaint905621 @Compassionate @phi @math&ing001 @acxbox22

2 Answers

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13/16
Because there are all together there are 16 people, 4 are doctors and 9 are female nurses. So add 9 and 4 are you get 13 since the question is asking for females or doctors.
User Cornelius Wilson
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6 votes

Answer:


\bf \textbf{Probability that the person is female or a doctor = }(13)/(16)

Explanation:

Number of nurses in the hospital = 12

Number of doctors in the hospital = 4

Number of male nurses = 3

Number of male doctors = 2

Number of male persons = 5

So, Number of female persons = 16 - 5 = 11

Number of female doctors = 4 - 2 = 2

So, Probability that the person is female or a doctor = Probability that a person is female + Probability that a person is doctor - Probability that a person is female doctor


\implies\text{Probability that the person is female or a doctor = }(11)/(16)+(4)/(16)-(2)/(16)\\\\\implies\bf \textbf{Probability that the person is female or a doctor = }(13)/(16)

User Keyur Padalia
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