81.8k views
3 votes
How many moles of o are in 15.0 mol fe(no3)3?

User LeviZoesch
by
8.1k points

2 Answers

6 votes
n[Fe(NO₃)₃]=15.0 mol

n(O)=3×3×n[Fe(NO₃)₃]=9n[Fe(NO₃)₃]

n(O)=9×15.0=135.0 mol
User Jannatul
by
8.6k points
1 vote

Answer : The number of moles of oxygen atoms are 135 moles.

Explanation : Given,

Moles of
Fe(NO_3)_3 = 15.0 mole

The given chemical formula is,
Fe(NO_3)_3

By the mole concept:

In
Fe(NO_3)_3, there are 1 mole of iron (Fe) atom, 3 moles of nitrogen (N) atoms and 9 moles of oxygen (O) atoms.

As, 1 mole of
Fe(NO_3)_3 contains 9 moles of oxygen atoms

So, 15.0 moles of
Fe(NO_3)_3 contains
15.0* 9=135 moles of oxygen atoms.

Hence, the number of moles of oxygen atoms are 135 moles.

User Pconrey
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.