Question

The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = 1/2 (x – 1). What is the slope-intercept form of the equation for this line?

Answer 1

You just have to simplify that point-slope equation in order to get it into slope-intercept:

`y-3= (1)/(2) (x-1)`

`y-3= (1)/(2)x- (1)/(2)`

`y= (1)/(2) x- (1)/(2) +3`

`y= (1)/(2) x- (1)/(2) + (6)/(2)`

`y= (1)/(2) x+ (5)/(2)`

Answer 2

`y=(x)/(2)+(5)/(2)`

Explanation:

Hello

thanks for asking this question, I think I can help you with this

if you have the point-slope form of the equation of a line, just isolate "y" to find the slope-intercept form

Step 1

`y-3=(1)/(2) (x-1)\\\\y-3=(x)/(2)-(1)/(2) \\Add\ 3\ in\ both sides\\\\y-3+3=(x)/(2)-(1)/(2) +3\\y=(x)/(2)-(1)/(2)+3\\y=(x)/(2)+(5)/(2)`

so the answer is

`y=(x)/(2)+(5)/(2)`

where 1/2 is the slope, and 5/2 is the intercept with y-axis

I really hope it helps , Have a great day.