Question

A game is biased such that the choices A-J have the following probabilities of winning: A 5% B 10% C 15% D 5% E 5% F 25% G 10% H 10% I 10% J 5% If you chose the letters D and H for 20 turns, how many times are you most likely to win? 1 2 3 4 5

Answer 1

C: 3

Explanation:

Answer 2

Since we have chosen 2 letters, then the total probability of winning the game is the sum of the probabilities of each letter. Therefore:

Total probability of winning = Probability of D + Probability of H

Total probability of winning = 5% + 10%

Total probability of winning = 15%

Since we are playing the game for 20 turns, therefore out of those 20 games, we will win 15% of the time. So:

15% = 0.15

Winning times = 0.15 * 20

Winning times = 3

Therefore we have a chance or probability to win at least 3 games out of 20 turns.