Question

Vincent is giving cakes to some children at a carnival. He has 2 strawberry cakes, 6 pineapple cakes, and 7 chocolate cakes. If Vincent selects a cake randomly without looking, what is the probability that he will give a pineapple cake to the first child and then a strawberry cake to the second child? (5 points)

6 over 15 multiplied by 2 over 14 is equal to 12 over 210

6 over 15 plus 2 over 14 is equal to 114 over 210

6 over 15 multiplied by 2 over 15 is equal to 12 over 225

6 over 15 plus 2 over 15 is equal to 8 over 15

Answer 1

`(12)/(210)`

Explanation:

Strawberry cakes = 2

Pineapple cakes = 6

Chocolate cakes = 7

Total cakes = 15

Now we are given that Vincent selects a cake randomly without looking, and he will give a pineapple cake to the first child

So, probability of getting a pine apple cake in first draw =
`\frac{\text{No. of pineapple cakes}}{\text{Total no. of cakes}}`

=
`(6)/(15)`

Now total no. of remaining cakes = 15-1 =14

Now we are given that Vincent selects a cake randomly without looking, and he will give a strawberry cake to the second child

So, So, probability of getting a strawberry cake in second draw=
`(2)/(14)`

So, the probability that he will give a pineapple cake to the first child and then a strawberry cake to the second child =
`(6)/(15) *(2)/(14)`

=
`(12)/(210)`

Hence Option A is true.

The probability that he will give a pineapple cake to the first child and then a strawberry cake to the second child is
`(12)/(210)`

Answer 2

2+6+7 = 15 total cakes

6 pineapple so probability is 6/15

then there would be 14 cakes

2 strawberry for a probability of 2/14

6/15 x 2/14 = 12/210

the first answer is the right one