Question

The function y=-2+5sin(pi/12(x-2)), what is the minimum value?

Answer 1

-7

Explanation:

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Answer 2

-7

Explanation:

We are given that a function

`y=-2+5 sin((\pi)/(12)(x-2))`

We have to find the minimum value of y.

We know that range of sin x is [-1,1].

`-1\leq sin((\pi)/(12)(x-2))\leq 1`

`-5\leq 5sin((\pi)/(12)(x-2))\leq 5`

`-5-2\leq -2+5sin((\pi)/(12)(x-2))\leq 5-2`

`-7\leq -2+5sin((\pi)/(12)(x-2))\leq 3`

`-7\leq y\leq 3`

Maximum value of y=3

Minimum value of y=-7

Hence, the minimum value of given function =-7