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What's the solution to |1x-12| < 15

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Start with |1x - 12| < 15. Add 12 to both sides. Then |1x - 12 + 12| < 15 + 12

Simplifying, |x| < 27. Then the two solutions are x < 27 and x > -27. In words, the solution set is the set of all x greater than -27 and less than +27.
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